HELP PLEASE must show work​

Classify the same terms in each question. It will help you to solve it easier.

1- 3x +4x +2 +6 = 7x +8

2- 2x +x +y -y +3z +z = 3x + 4z (we didn't put y because +y -y =0 )

3 -
[tex] {x}^{2} + {x}^{2} + 2 - 5 = 2 {x}^{2} - 3[/tex]
4-
[tex]3 {a}^{2} + {a}^{2} + 2a + a - 1 + 1 = 4 {a}^{2} + 3a[/tex]

( a and a^2 aren't the same because a's exponent is one , but a^2 's exponent is two.)

5-
[tex] 2{x}^{2} + {x}^{2} + 3x - x - 1 + 2 = 3 {x}^{2} + 2x + 1[/tex]
6-
[tex]2z - 3z - {z}^{2} + {z}^{2} + 5 + 1 = - z + 6[/tex]
7-
[tex] - 2 {t}^{2} + {t}^{2} - t + t + 3 - 3 = - {t}^{2} [/tex]
8-
[tex](4m - 2n) - (3m + 3n) = [/tex]
we should distribute (-) to numbers in pharantesis after (-) so we can get the correct result.

[tex]4m - 2n - 3m - 3n[/tex]
now we can classify

[tex]4m - 3m - 2n - 3n[/tex]
= m-5n

9- (same technique with the previous one)

[tex]6a - 2b - 7 - a + b - 2[/tex]

- (a -b+2 ) = -a+b-2
[tex]5a + 3b - 9[/tex]

10-

[tex]7 - 3 {q}^{2} [/tex]
(-3q^7 +7 is possible too)

11-

[tex]6 {d}^{2} + 3d + 1 - {d}^{2} + 3d + 5 = 5 {d}^{2} + 6d + 6[/tex]

Hope it helps!
#MissionExam001